Ab and CD bisect each other at k. Prove that Ac =bd please give answers
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Step-by-step explanation:
When u will draw the figure u will find two triangles AKC and ∆ DKB
In whichAK=BK AB is bisected at K
CK=DK CD is bisected at K
Angle AKC=angleBKC vertically opposite angles
Therefore,∆AKC=~∆DKB
Hence by CPCT, AC = BD
Hence prove
Hope it helps u
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