AB and CD intersect at point O such that AO=OB and OC =OD . find the third pair of corresponding parts to make the two triangles congruent by side angle side . write the congruence of two triangles in the symbolic form
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In ∆ACO and ∆DOB
AO = OD (given)
OC = OB (given)
<AOC = <BOD (vertically opposite angel)
So, by SAS (side angle side) congruency rule
∆ACO ≈ ∆DOB
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