AB and CD intersect each other at E such that DE=BE and EA=EC show that AD=CB
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Step-by-step explanation:
GIVEN- AE=CE
DE=BE
TO PROVE- AD = CB
PROOF- In triangle AED and CEB
AE =CE (GIVEN)
DE = BE (GIVEN)
Angle AED= Angle CEB ( VERTICALLY OPP. ANGLES)
SO ∆ AED is congruent to ∆ CEB
BY CPCT AD = CB
HENCE PROVD
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