AB and co are two chard.
og
circle such that
ABU en A Beloem, CD = 24cm.
The distence between the chords is 17cm
radius of the circle.
find the
Answers
Answered by
0
Answer:
idk..............
......
Answered by
1
Answer:
Let ON = x
On rt ΔOMC
OB
2
=OM
2
+MB
2
=(17−x)
2
+5
2
....(i)
In rt. ΔOND,
OD
2
=ON
2
+ND
2
=x
2
+12
2
....(ii)
But OB
2
=OD
2
[∵ OB and OD being the radii of the same circle are equal]
∴x
2
+12
2
=(17−x)
2
+5
2
⇒x
2
+144=289+x
2
−34x+25
⇒34x=289+25−144=170
⇒x=
34
170
=5
Hence from (2)
OD
2
=5
2
+12
2
=25+144
=169=13
2
∴OD=13
Hence the radius of the circle is 13 cm.
Step-by-step explanation:
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