Question

AB and DC are two vertical poles placed opposite to each other at a distance of 36 m from each other such that the points B and D are at ground level. If the length of AB is 30 m and the length of CD is 15 m, find AC. (Hint: Draw CE ⊥ AB and join AC.)

Answer 1

Answer:

39

Step-by-step explanation:

by using the pythagorean theorem

Answer 2

AC=39 m.  

Step-by-step explanation:

Given:

As shown in the figure below, AB and DC are two vertical poles placed opposite to each other.

Distance between the two vertical poles = BD = 36 m.

AB = 30 m, CD = 15 m.

In triangle AEC ,

angle E=90 degrees     [ given CE ⊥ AB]    

Also, BE = CD         [given]

∴ BE = 15 m            [given CD = 15 m]

AE = 15m                 [AE=AB-BE]

In Δ AEC,

By Pythagoras theorem,

$AC^2=AE^2+EC^2$

$15^2+36^2=AC^2$

$225+1296=AC^2$

$1521=AC^2$

$AC=\sqrt{1521}$

AC=39 m.