AB + BC = 18 AB^2 +BC^2=164 find length of AB
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Step-by-step explanation:
ABCD rectangle
Perimeter = 36 cm
diagonal AC = √164 = √(41*4)=2√41 cm.
AB+BC= 36/2=18.
(AB+BC)^2=18^2
AB^2+BC^2+2*AB*BC=(20-2)^2=400–80+4=324
AB^2+BC^2=AC^2=(√164)^2=164
164+2*AB*BC=324
2*AB*BC=324–164=160
AB*BC=80
(AB-BC)^2=AB^2+BC^2–2*AB*BC=164–2*80=4
AB-BC=2
AB+BC=18
2AB=20
AB =10
BC =8
AC =√164
AB+AC =10+√164 cm
AB= 10 cm
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