(ab + bc) ^2 - 2ab^2 c
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Answered by
1
Answer:
=(a^2b^2 + b^2c^2 + 2abbc) -2ab^2c
=a^2b^2 + b^2c^2
Answered by
0
Step-by-step explanation:
a^2b^2+2ab^2c+b^2c^2-2ab^2c
a^2b^2+b^2c^2
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