Question

(ab+bc)^2−2ab^2c help me plz​

Answer 1

Answer:

Step-by-step explanation:

(ab+bc)²-2ab²c

(ab+bc)(ab+bc)-2ab²c

a²b²+ab²c+ab²c+b²c²-2ab²c

a²b²+2ab²c+b²c²-2ab²c

=a²b²+b²c²

Answer 2

Step-by-step explanation:

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