Question

(ab+BC)(ab-bc)+(BC+ca)(bc-ca)+(ca+ab)(ca-ab)=0

Answer 1

Answer:

0

Step-by-step explanation:

(ab) ²-(bc) ²+(bc) ²-(ca) ²+(ca) ²-(ab) ²

=0

Answer 2

Answer:

proved

Step-by-step explanation:

as the formula

$(a + b)(a - b) = {a}^{2} - {b}^{2}$

$so \: \\ {(ab)}^{2} - {(bc)}^{2} + {(bc)}^{2} - {(ca)}^{2} + {(ca)}^{2} - {(ab)}^{2}$

$0$