AB, BC and CD are the three consecutive sides of a regular polygon. If angleBAC= 15degree; find
(i) each exterior angle of the polygon.
(ii) each interior angle of the polygon
(iii) number of sides of the polygon
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Since AB=BC, ABC I an isosceles triangle, hence angle ACB= angle BAC=15 degree therefore angle ABC=150 degree
Thus each interior angle=150degree
Each exterior angle= 30 degree
Number of sides= 360/30 = 12
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Answer:
interior angle=150
exterior angle=30
no. h of sides=12
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