AB=BC,ANGLE B=80°,SO SOLVE THE MEASURE OF ANGLE A IN ∆ ABC.
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it is an isoceles triangle so angle A = angle C = X
angle A + angle B + angle C = 180 ( angle sum property of triangle)
X + 80 + X = 180
2x = 100
X = 50 °
angle A = 50°
angle A + angle B + angle C = 180 ( angle sum property of triangle)
X + 80 + X = 180
2x = 100
X = 50 °
angle A = 50°
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