Math, asked by pksgupta7108, 1 year ago

AB *BC=(B+1)CB Find the value of (ABC)

Answers

Answered by TheLostMonk

0

A B× BC =( B+ 1 ) CB

AB^2C = B^2C + BC

B(ABC) = B ( BC + C)

ABC = BC + C

ABC= C( B + 1)

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