AB *BC=(B+1)CB Find the value of (ABC)
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A BĂ— BC =( B+ 1 ) CB
AB^2C = B^2C + BC
B(ABC) = B ( BC + C)
ABC = BC + C
ABC= C( B + 1)
AB^2C = B^2C + BC
B(ABC) = B ( BC + C)
ABC = BC + C
ABC= C( B + 1)
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