Math, asked by simmba37, 9 months ago

(ab-bc) + (bc-ca) + (ca-ab)​

Answers

Answered by brijeshhkumar1980
3

Answer:

0

Step-by-step explanation:

ab-bc+bc-ca+ca-ab

=0

plz mark brainleist . . follow for every answer instatntly

Answered by MaIeficent
31

Answer:

\mathbf\red{To\:Find}

\tt{The\:value\:of:-\: \\ \\  (ab-bc)+(bc-ca)+(ca-ab)}

\mathbf\green{Solution:-}

\tt{Given:-\: (ab-bc)+(bc-ca)+(ca-ab) \\ \\</p><p></p><p>Remove\: all\: the \:brackets\\ \\</p><p></p><p>We\:get\\ \\</p><p></p><p> ab-bc+bc-ca+ca-ab \\ \\</p><p></p><p>Rearrange\:all\:the\:like\:terms\\ \\</p><p></p><p>=ab-ab+bc-bc+ca-ca\\ \\</p><p></p><p>= 0}

\large\orange{\underline{{\boxed{\textbf{#Be\:Brainly}}}}}

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