Math, asked by simmba37, 8 months ago

(ab-bc) + (bc-ca) + (ca-ab)

Answers

Answered by hemantbhushan1761

3

Answer:

(ab-bc) + (bc-ca) + (ca-ab)

= ab- bc + bc - ca + ca - ab

= 1

I hope it help you.

Answered by Anonymous

13

Answer:

1. (ab-bc)+(bc-ca)+(ca-ab)

= ab-bc+bc-ca+ca-ab

= ab-ba-bc-bc-ca+ca

= 0

Hope it helps you dear✌✌

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