ab+bc+ca=36 and a²+b²+c²=85 then find a+b+c
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Answered by
9
hey mate here's ur ans ↓↓
=(a+b+c)^2
=a^2+b^2+c^2+2ab+2bc+2ca
=85+2(36)
=72+85
=157
Now,a+b+c=√157
a+b+c=12.599....
hope it helps u☺☺✌
=(a+b+c)^2
=a^2+b^2+c^2+2ab+2bc+2ca
=85+2(36)
=72+85
=157
Now,a+b+c=√157
a+b+c=12.599....
hope it helps u☺☺✌
Answered by
1
(a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab+bc+ac)
=85+2(36)
= 85 + 72
157
(a+b+c) = root of 157
=85+2(36)
= 85 + 72
157
(a+b+c) = root of 157
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