ab+bc+ca * -a
Pls solve fast
Answers
Answered by
0
abc(
a
1
+
b
1
+
c
1
)
Let us take abc common from (ab+bc+ca) then we get:
abc(
c
1
+
a
1
+
b
1
)
⇒abc(
a
1
+
b
1
+
c
1
)
Hence, (ab+bc+ca) can be expressed as abc(
a
1
+
b
1
+
c
1
)
Answered by
0
Answer
abc(
a
1
+
b
1
+
c
1
)
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