Question

ab+bc+ca this is my question

Answer 1

Step-by-step explanation:

Hence, (AB)²+(BC)²+(CA)²+2AB²C+2ABC²+2A²BC. (AB)²+(BC)²+(CA)²+2ABC(B+C+A).

Answer 2

Answer:

As per the identity,

(x+y+z)2=x2+y2+z2+2xy+2yz+2zx

Here, x = AB, y = BC and z = CA

Putting this value,

(AB+BC+CA)2=AB2+BC2+CA2+2AB.BC+2BC.CA+2CA.AB

(AB+BC+CA)2=AB2+BC2+CA2+2ABC[B+C+A]

Rewriting,

(AB+BC+CA)2=AB2+BC2+CA2+2ABC[A+B+C]

Hope it helped you!