AB = BC = ........................)
V8
<BAC = 0
AB=BC = OXAC
B
C
=OX V8
= 0X 2/2
Answers
Answered by
1
Answer:
Let (α,β),(β,r),(r,α) be the roots respectively .
Then, α+β=−a;β+r=−b;r+α=−c
α+β+β+r+r+α=−(a+b+c)
α+β+r=−
2
(a+b+c)
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