AB=BD and CA =DC .Is ∆BAC=~∆BDC .Is <ABC= <CBD ?
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shwetasharma19:
second part ki full explanation do
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Step-by-step explanation:
given ab= bd
ca=dc
proof - in ∆abc =∆ bcd
ab=bd
ca=dc
bc=bc
so bac =~bdc (sss congruence rule)
2) <Abc =<cbd
(correspending angles of
)
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