Question

AB bisects LA. AC= 3 AB
Le
find
BD: DC
B
D
с.
AR​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

∆PQR = 28 cm

Solution:-

in ∆PQR

PQ = QR = 10 cm

∴ ∠PQR =∠CQA (Angles opposite to equal sides are equal)

However ,

∠PQR = ∠CQA ( vertically opposite angels)

=> ∠CQA = ∠PRQ = ∠NRB .... (1)

in ∆ AQC and ∆ BRN

AQ = BR (given)

∠ACQ=∠BNR = 90°

∠CQA = ∠NRB [ From EQ 1]

∴ ∆ AQC ≅ ∆ BRN (A-A-S)

=> CQ = NR and AC = BN (c.p.c.t)

CQ = 1 cm

NR = 1 cm

CM= CQ + QM = (1+3)cm = 4cm

in ∆CAM and ∆ NBM

CA = NB

∠MCA =∠ MNB = 90°

∠AMC = ∠BMN ( vertically opposite angels)

∴ ∆ CAM ≅ ∆ MNB (A-A-S)

=> CM = MN (c.p.c.t)

CM= 4cm , MN = 4cm

∴ QR = QM +MN + NR =( 3+4+1) cm = 8cm

Perimeter of ∆PQR = PQ+QR+PR = (10+8+10) = 28 cm

Thus, the perimeter of ∆PQR is 28 cm