Question

AB||BQ||CR.prove that area of ∆AQC=area of ∆PBR​

Answer 1

Two Triangles on the same base and between

the same parallels are equal in area.

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Given,

AP || BQ

|| CR

To Prove,

ar(∆AQC)

= ar(∆PBR)

Proof:

ar(△AQB) = ar(△PBQ) — (i)

(On the

same base BQ and between the same parallels AP and BQ.)

also,

ar(△BQC) = ar(△BQR) — (ii)

 (On the same base BQ and between the same

parallels BQ and CR.)

Adding (i) and (ii),

ar(△AQB) +

ar(△BQC) =

ar(△PBQ) +

ar(△BQR)

 ar(△ AQC) = ar(△ PBR)

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Hope

this will help you...