(ab-c)²+2abc using identity
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0
Answer:
here you go
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i hope its help you thanks:)
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Answered by
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Answer:
ab - c)2 + 2abc
= (ab)2-2(ab)(c) + (c)2 + 2abc
= a2b2-2abc + c2 + 2abc
= a2b2 + c2
Therefore, (ab - c)2 + 2abc = a2b2 + c2
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