Math, asked by wwwpallavimallick371, 1 month ago

(ab-c)²+2abc using identity

Answers

Answered by kumarijyotisp18

0

Answer:

(ab - c)2 + 2abc

= (ab)2-2(ab)(c) + (c)2 + 2abc

= a2b2-2abc + c2 + 2abc

= a2b2 + c2

Therefore, (ab - c)2 + 2abc = a2b2 + c2

Answered by Anonymous

5

Answer:

(ab - c)2 + 2abc

= (ab)2-2(ab)(c) + (c)2 + 2abc

= a2b2-2abc + c2 + 2abc = a2b2 + c2

Therefore, (ab - c)2 + 2abc = a2b2 + c2

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