ab c ka whole square
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Answer:
To find :
(a-b-c)²
Solution :
(a - b - c )²
This can be split up as,
= ( a - b - c ) ( a - b - c )
Multiplying both the terms, we get,
= a ( a - b - c ) - b ( a - b - c ) - c ( a - b - c )
= a² - ab - ac - ab + b² + bc - ac + bc + c²
= a² + b² + c² - 2ab + 2bc - 2ac
Therefore,
( a - b - c )² = a² + b² + c² - 2ab + 2bc - 2ac
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