Question

(ab+cd)
^2-2abcd find answer using identity. who so ever give right answer I would mark him braniest.​

Answer 1

$Given \: (ab+cd)^{2} - 2abcd$

$= (ab+cd)^{2} - 2\times (ab)(cd)$

/* By algebraic identity */

$\boxed{ \pink{ (x+y)^{2} - 2xy = x^{2} + y^{2} }}$

$= (ab)^{2} + (cd)^{2}$

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