AB||CD,AF||ED, ANGLE AFC=68° and ANGLE FED=42°<. Find ANGLE EFD.
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can you send the pic of figure
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Answer:
Step-by-step explanation:
Concept: Lines that are parallel to one another on a plane do not intersect or meet at any point. They are always equidistant from one another and parallel. Non-intersecting lines are parallel lines. Parallel lines can also be said to meet at infinity.
Given: AB || CD
AF || ED
∠AFC = 68°
∠FED = 42°
To find: ∠EFD
Solution: Since AB || CD and AF is the transversal, then ∠AFC = ∠EDF = 68°(corresponding angles)
In ΔEFD, ∠FED = 42°, ∠EDF = 68°
therefore, applying the angle sum property of a triangle
∠FED + ∠EFD + ∠EDF = 180°
42° + ∠EFD + 68° = 180°
∠EFD + 110° = 180°
∠EFD = 180° - 110°
∠EFD = 70°
Hence ∠EFD = 70°
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