Question

AB || CD and I
is a transversal which
intersects AB and CD at E
and F, respectively.​

Answer 1

Correct Question:

• AB || CD and t is a transversal which intersects AB and CD at E and F, respectively. if ∠2:∠1=5:4, find the measure of each marked angles.

Solution:

• AB || CD and t is a transversal. Also
• Angle 2:Angle 1= 5:4
• 5x+ 4x = 180(Linear pair)
• x=20 so, Angle 1 =70°
• Angle 1 = Angle 4(Vertically opposite angle)
• Angle 4 =70°
• Angle1 +Angle 3= 180°(Linear Pair)
• Angle 3 +70=180°
• Angle 3 =180-70
• Angle 3 =110°
• Also ,we have,
• Angle 2 =Angle 3(V.O.A)
• Angle 2 =110° Now we Have,
• By corresponding Angles =>Angle 1=Angle 5 => Angle 2 =Angle 8=>Angle 3= Angle 6=>Angle 4= Angle 7.
• Therefore, We get
• => Angle 5=70°
• => Angle 6=110°
• =>Angle 7= 70°
• =>Angle 8=110°
• Hence, All Angles are identified.

Thanks!..