Question

AB, CD and PQ are three lines concurrent at O. If angle AOP =5y, angle QOD =2y and angle BOC=5y ,find the value of y

Answer 1

Answer:

y=15°

Step-by-step explanation:

angle AOP = angle BOQ(alternate angles)

angle AOP=5y

therefore, angle BOQ = 5y

angle BOC = angle AOD (alternate angles)

angle BOC = 5y

therefore, angle AOD = 5y

angle QOD = angle POC (alternate angles)

angle QOD = 2y

therefore, angle POC = 2y

sum of all the angles = 360°

therefore, angle AOP + angle POC + angle BOC + angle BOQ + angle QOD + angle DOA = 360°

5y + 2y + 5y + 5y + 2y + 5y = 360°

24y = 360°

y = 360°/ 24 = 15°

Answer 2

After finding all the angles you with the help of Vertically opposite angle you can you this step.

24y=360

y=360/24

y=15

Some steps you can refer the picture