AB//CD angel BDC=40 and angle BAD=75
FIND X; Y;Z
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Here, CDA= 40= x ( alternate angle)
Now, in triangle DAB x= 40 angle A = 75 .
sum of a triangle is 180, so
y+75+40=180
y=180-115=65
now in other triangle angle CBD = 65-5 = 60
same method , propertry of triangle
so,
40 +60+z=180
z=180-100=80
Now, in triangle DAB x= 40 angle A = 75 .
sum of a triangle is 180, so
y+75+40=180
y=180-115=65
now in other triangle angle CBD = 65-5 = 60
same method , propertry of triangle
so,
40 +60+z=180
z=180-100=80
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5
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refer to attachment........above
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