Question

AB || CD, angle APQ = 70degree and angle PRQ=56degree find x and y

guys plz any maths legends answer this question plz​

Answer 1

Answer:

∠APQ = 50°(Given)

⇒ ∠PQR = 50°(Alternate interior angles)

∠PRD = 130°(Given)

∠PRD = (180°- 130°) = 50° (Forms a Linear pair)

Sum of interior angles of a triangle = 180°

∠ QPR = 180°- ∠PQR-∠PRD

∠ QPR = 180°-100°

∠ QPR = 80°

Answer 2

Answer:

∠PQR=∠APQ (Alternate angle)

x=50

∘

∠PRQ+∠PRD=180

∘

∠PRQ+127

∘

=180

∘

∠PRQ=180

∘

−127

∘

=53

∘

∠PQR+∠QPR+∠PRQ=180

∘

(Angle sum property of trianlge

x+y+53

∘

=180

∘

50

∘

+y+53

∘

=180

∘

y=180

∘

−103

∘

=77

∘