AB=CD, CB=OC and angle ABD=angle DCA prove that AC=BD
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given,
AB=CD
CB=OC
angle ABD=angle DCA
In trianlgle ABC and trianlgle DCA
AB=CD (given)
CB=CB(common)
angle ABD = angle DCA (given)
so,
trianlgle ABC congruent to trianlgle DCA
(by SSA rule)
hence,
AC=BD (congruent side) proved.
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