Math, asked by Anonymous, 11 months ago

AB=CD, CB=OC and angle ABD=angle DCA prove that AC=BD​

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Answered by stp2965
2

solution -

given,

AB=CD

CB=OC

angle ABD=angle DCA

In trianlgle ABC and trianlgle DCA

AB=CD (given)

CB=CB(common)

angle ABD = angle DCA (given)

so,

trianlgle ABC congruent to trianlgle DCA

(by SSA rule)

hence,

AC=BD (congruent side) proved.

Thanks ❤

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