Question

AB||CD
EF||DQ
find , x ,y,z​

Answer 1

Answer:

Given : AB∣∣CD;EF∣∣DQ

To find : ∠PDQ

∵AB∣∣CD and PE is transversal

∠PDC and ∠PEA are corresponding angles.

∴PEA=34

∘

∠PEA+∠PEF+∠FEB=180

∘

(Linear pair)

34

∘

+∠PEF+∠FEB=180

∘

∠PEF=180

∘

−34

∘

−78

∘

∠PEF=68

∘

∵EF∣∣DQ

∠PDQ=∠PEF=68

∘

∴∠PDQ=68

∘