AB || CD find x°
please explain don't write direct answers plzzzzzzzzzzzz
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AB||CD
draw a line EF passing through O.
therefore, AB||EF||CD
angle ABO=40°
angle EOB+angle ABO=180°(supplementary angles)
angle EOB+40°=180°
angle EOB=180°-40°
angle EOB=140°
angle CDO=35°
angle EOD+ angle CDO=180°(supplementary angles)
angle EOD+35°=180°
angle EOD=180°-35°
angle EOD=145°
angle EOD+angle CDO=x
145°+140°=x
285°=x
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