AB||CD if <ABC=45°,<COD=100°, find <ODC
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Answer:
35°
Step-by-step explanation:
<AOB=<COD= 100° ( Vertically opposite )
In ∆ AOB,
<AOB+<ABO+<BAO= 180°
=> <BAO= 180° - ( 100°+ 45° )
=> <BAO= 35°
Now, AB||CD and AD is a transversal
So, <D= <BAO= 35° ( co interior )
Hence, <ODC = 35°
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