Question

AB||CD in trapezium ABCD. If angle A=70 and amgle B=85,then find angle D​

Answer 1

The value of $\angle D$ is $110\ degree$

Step-by-step explanation:

Given,

$AB\parallel CD$ in trapezium $ABCD$ where $\angle A=70\ degree$ and $\angle B=85\ degree$

Find $\angle D=?$

In any trapezium,

Two angles on the same side are supplementary, that is the sum of the angles of two adjacent sides is equal to $180\ degree$

So, From figure,

$\angle A+\angle D=180$

⇒$\angle D=180-70$

∴ $\angle D=110\ degree$

Hence, The value of $\angle D$ is $110\ degree$

Answer 2

The value of angle D in the trapezium ABCD when AB║CD and ∠A = 70° is 110°

• Given

                 AB║CD, ∠A = 70°, ∠B = 85°

• If  AB║CD, AD and BC are transversals.

• We know that, "The interior angles formed on the same side of the transversal are supplementary"
• ∠A and ∠D are on same side of transversal

                   ∠A + ∠D = 180

                   70 + ∠D = 180

                    ∠D = 180 - 70

                    ∠D = 110°