Question

AB||CD in trapezium ABCD, if angle A=y+60°, angle B=x+60°, angle c=3x-40°and angle D =3y-80°, then find all the values of ABCD.plzzzzz do fast it's urgent​

Answer 1

since AB//CD so angle A +angle D=180 (sum of co interior angles) y+60+3y-80=180; 4y-20=180;4y=180+20;4y=200;y=50 A=50+60 =110; D=50×3-80=70