Question

AB||CD in trapezium ABCD. if angle a=y+60andangle b =x+60and angle c=3x-40and angle d=3y-80,then find all the angels of abcd​

Answer 1

Answer:

Step-by-step explanation:

A + D = 180° (sum of adj. angles)

y + 60° + 3y - 80° = 180°

4y - 20° = 180°

4y = 180° + 20° = 200°

y = 200°/4 = 50°

Similarly

B+C = 180

x+60+3x-40 = 180

4x+20=180

4x=180-20=160

X = 160/4=40

Now put the values of x and y in the expressions