AB=CD
Prove That
triangle OAB=triangle ODC
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Answer:
Given that AB=CD
here we get OA=OB=OC=OD [ all are radii of the same circle]
we have
OA=OC
OB=OD
AB=CD
Therefore by SIDE SIDE SIDE (SSS)congruence theorem
triangle OAB=triangle ODC
Hence proved
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