Question

AB|| CD , QO  6cm and OB 8cm, find OPOD.

Answer 1

Perpendicular drawn from centre of a circle to chord bisects the chord.

AC=BC=12cm

And ∠OCB=90

∘

Thus, triangle OCB is a right angled triangle

OB=13cm.

Therefore by Pythagoras theorem

OB

2

=OC

2

+BC

2

OC

2

=OB

2

−BC

2

OC=

13

2

−12

2

OC=5cm