Math, asked by preethikowsalya, 8 months ago

AB||CD, x=4y/3,y=3z/8 where angle BDA=36°,angle ABD=X, angle DBC=Y,angle C= Z
find the angles
BCD
DBA
BAD​

Answers

Answered by ranjanasahay838
0

Answer:

In the figure AB||CD, If x=4/3y and y=3/8z find angle BCD, angle ABC and ... y = 36. x = 4y/3 = 4 * 36/3 = 48. x = 48. z = 8y/3 = 8 * 36/3 = 96. z = 96 ... if x=4y/3. if y=3z/8. y/3/8= z. 8y/3 = z. now,. since, AB||CD. x + y+ z + = 180 .

Step-by-step explanation:

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