Question

AB completes a piece of work in 12 days and CD completes the same work in 18 days. In how many days will they together complete the same work ?​

Answer 1

Answer:

Given:

A alone can do work = 12 days

B alone can do work = 18 days

A, B, and C together can do the same work = 6 days

Concept:

The work = Time × Efficiency

Calculation:

Let be assume C can complete the work in C days

⇒ The efficiency of A = 1/12

⇒ The efficiency of B = 1/18

⇒ The efficiency of A, B and C = 1/6

⇒ (1/12 + 1/18 + 1/C) = 1/6

⇒ 1/C = (1/6 - 1/12 - 1/18) = (6 - 3 - 2)/36 = 1/36

⇒ C can complete the work = 36 days

∴ The required result will be 36 days.