Question

AB crystallises in a body centered cubic lattice with edge length a equal to 387 pm. The distance between two oppositely charged ions in the lattice is​

Answer 1

As given in the question, we have;

The length of the edge of the cubic lattice  = a = 387 $pm$

∴ The distance between two oppositely charged ions in the lattice is equal to;

$(r^++r^-) =$ $\frac{a\sqrt{3}}{2} = \frac{387 * \sqrt{3}}{2} =$ 333.15 $pm$

Ans) The distance between two oppositely charged ions in the body centered cubic lattice is 333.15 $pm$