Question

AB crystallizes in a body centred cubic lattice with edge length 'a' equal to 387 pm. The distance between two oppositively charged ions in the lattice is

Answer 1

Answer:

Explanation:

in BCC the constituent atoms are present at body centre(let it be A) and at corners(let it be B )of the lattice.

so distance between A and B will be half of diagonal.

i.e  √3a/2

= √3 × 387/2

= 1.732 × 387/2

=335.1 pm