AB||DC and AD||BC if DAB is 75 find the measures of a b c
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Given:-
AB ║ DC and AD ║ BC
and, ∠DAB = 75°
Solution:-
Here, AD ║ BC and AB is transversal
∵ Consecutive interior angles are supplementary
∴ ∠DAB + ∠ABC = 180° [ AD ║ BC and they are Consecutive interior angles ]
so, 75° + ∠ABC = 180°
⇒ ∠ABC = 180° - 75°
⇒ ∠ABC = a = 105°
Now, AB ║ DC and BC is transversal
∵ Consecutive interior angles are supplementary
∴ ∠DCB + ∠ABC = 180° [ AB ║ DC and they are Consecutive interior angles ]
so, ∠DCB + 105° = 180°
⇒ ∠DCB = 180° - 105°
⇒ ∠DCB = b = 75°
Now, AD ║ BC and DC is transversal
∵ Alternate interior angles are Equal in measure
∴ ∠DCB = ∠EDC [ AD ║ BC and they are Alternate interior angles ]
⇒ ∠EDC = c = 75°
Hence, a = 105° and b = c = 75°
Some important terms:-
- When two parallel lines intersected by a transversal then:-
- Alternate interior angles are equal.
- Alternate exterior angles are equal.
- Corresponding angles are equal.
- Consecutive interior angles are supplementary.
- Vertically opposite angles are equal.
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