.. AB - DETA-
(2) In A ABC, 2 ACB is obtuse angle, seg AD I seg BC. Prove that:
ABP = BC + AC + 2BC X CD
In the figure seg AD I seg BC
Let AD = P, AC = b. AB = c.
BC = a and DC = r.
DB = a +r
In A ADB, by Pythagoras theorem,
c = (a+x) +p:
Fin2 24
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