AB is 6 AC is 8 BC is 10
AD is the median of side BC. Find the length of AD.
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f we can know the length of BD we can find out AP and QC
since BP=BQ=BD=radius
now there are two ways to find out the length of BD
one is using pythagoras theorem another is using area(hero's formula)
pythagoras :
BD^2=AB^2-AD^2=BC^2-DC^2{DC=AC-AD}
using the above eqn we will get BD=24/5
AP=6-24/5=6/5
QC=8-24/5=16/5
ratio=6/16=3/8
hero's formula
s=a+b+c/2=(6+8+10)/2=12
area=Sqrt(s(s-a)(s-b)(s-c)=24
area is also=1/2 * BD*AC=5BD
so BD=24/5
rest is same
Step-by-step explanation:
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