Question

ab is a chord of a circle having centre o. if angle aob = 90°, prove that the chord ab is of length r√2, where r = radius​

Answer 1

Answer:

OA=OB= r

angle AOB=90 degree

(OA)^2 +(OB)^2 = (AB)^2

AB=($\sqrt{r^2 +r^2}$)

AB= r$\sqrt{2}$

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Answer 2

Answer:

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