AB is a chord of a circle with center 0 and radius 4cm. AB is of length 4cm and divides the circle into two segments. find the area of the minor segment and major segment.(use under root 3=1.73
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Answer:
Step-by-step explanation:
As radius of the circle (r)=4cm
⇒ Length of the chord =4cm
∴ The triangle formed is equilateral triangle.
∴ θ=60
o
[ Angle of equilateral triangle is 60
o
]
⇒ Area of the sector =
360
o
θ
(πr
2
)
Where, θ is angle subtended at a center.
πr
2
is area of a circle.
⇒ Area of the sector =
360
o
60
o
×
7
22
×(4)
2
⇒ Area of the sector =
21
176
=8.38cm
2
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