AB is a chord of a circle with center O. If angle AOB = 90° and AB=3√2cm then the diameter of the circle is= (a) 3cm (b) 3√2/2 cm (c) 1.5 cm (d) 6cm
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hey mate
here is your answer
let the radius of the circle be x
by phythagoras theorem,
x²+x²=(3√2)²
2x²=18
x²=18/2
x=±3
but x≠-3
hence the radius of the circle is 3 cm
here is your answer
let the radius of the circle be x
by phythagoras theorem,
x²+x²=(3√2)²
2x²=18
x²=18/2
x=±3
but x≠-3
hence the radius of the circle is 3 cm
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