AB is a chord of a circle with center O . The tangent at B cuts AO produced at T. If angle BAT is 25 ,then the value of angle BTA
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Draw the perpendicular from point B to center O
From the property of the circle ,it is very clear that ∠BOT is double of ∠BAT .
Hence ∠BOT=50
o
Now In ΔBOT
∠TBO+∠BOT+∠BAT=180
o
Hence ∠BTA=180−(50+90)
∠BTA=40
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